When balancing the equation the variety of atoms in reactant side have to be equal to number of atoms in product side.

You are watching: Which sequence of coefficients will balance the following equation

The sequence the balance the equation above is 2,1,2 thus the balanced equation is as below.

2Ca (s) + O₂ → 2CaO (s)



2 ways Acceleration deserve to be readjusted are:i) boosting or decreasing the velocity the a moving object.ii) readjust of direction of the moving object.

See more: How Many Millimeters Are 18 Cm Equals How Many Millimeters Are 18 Centimeters



A tall, cylindrical chimney falls over as soon as its base is ruptured. Treat the chimney as a slim rod of length 58.8 m. At the insta

rememberingsomer.com:

Explanation:

Using conservation of mechanical power for rotational motion of chimney

gain of rotational KE = loss of potential power

1/2 Iω² = mgl/2 ( 1 - cosθ ) ; ns is minute of inertia , ω is angular velocity , m is mass of chilney , together is its length .

I = 1/3 m l²

1/6 m l²ω²= mgl/2 ( 1 - cosθ )

1/6 m v² = mgl/2 ( 1 - cosθ )

v² = 3gl( 1 - cosθ )

radial acceleration at the height = v² / r

=3gl( 1 - cosθ ) / l

= 3g ( 1 - cosθ )

= 3 x 9.8 ( 1 - cos 30.2 )

= 4 m / s²

b ) let angular acceleration it is in α .

Torque acting at the time

mgsinθ x together /2 = ns α

mgsinθ x l /2 = 1/3 m l² α

α = 3g sinθ / 2l

tangential acceleration

α x together = 3gsinθ / 2

= 3 x 9.8 sin 30.2 / 2

= 7.4 m /s²

c ) tangential acceleration equal to g

3gsinθ / 2 = g

sinθ = 2 / 3

42 level .


6 0
5 month ago

An astronaut hold a absent 100m above the surface of earth X. The rock is then thrown upward v a rate of 15m/s, as presented in
Airida <17>

rememberingsomer.com:

uwu

Explanation:

i dunno UnU


3 0
11 month ago

Use the Bohr version to deal with this question. Once a hydrogen atom provides a change from the 5 th power level to the 2nd, coun
iris <78.8K>

rememberingsomer.com:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculation the energy of the photon emitted you usage the adhering to formula:

*
(1)

n1: last state = 5

n2: initial state = 2

Where the energy is electron volts. You change the worths of n1 and n2 in the equation (1):

*

B. The power of the emitted photon is offered by the adhering to formula:

*
(2)

h: Planck"s continuous = 6.62*10^-34 kgm^2/s

c: speed of irradiate = 3*10^8 m/s

λ: wavelength the the photon

You first convert the energy from eV come J:

*

Next, you usage the equation (2) and also solve because that λ:

*

C. The radius the the orbit is provided by:

*
(3)

where ao is the Bohr"s radius = 2.380 Angstroms

You usage the equation (3) with n=5:

*

hence, the radius that the atom in that is 5-th state is 59.5 anstrongs


8 0
9 months ago

What room the potential hazards connected with utilizing coal
sergij07 <2.7K>
Coal build up when burned in chimneys and can get set ablaze and collection a home on fire!
7 0
7 month ago
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