We’re gift asked tocalculate the maximum fixed of waterthat will be formed in the reaction.

You are watching: Sulfuric acid and sodium hydroxide react to form sodium sulfate and water

For this problem, we must do the following steps:

Step 1:Write and also balance a chemistry equation because that the offered reaction.

Step 2:Determine the limiting reactant and also calculate the fixed of H2O formed.

Step 1: indigenous the problem, the given chemical reaction is:

H2SO4(aq) + NaOH(s)→Na2SO4(aq) + H2O(l)

This equation is not yet balanced. To balance it, we have to make certain that thenumber of aspects on both sides is equal.

Balance Na:We have 1 Na ~ above the reactant side and 2 Na ~ above the product side –add a coefficient the 2 come NaOH:

H2SO4(aq) +2NaOH(s)→Na2SO4(aq) + H2O(l)

Balance H:We have 4 H on the reactant side and 2 H on the product side –add a coefficient of 2 to H2O:

H2SO4(aq) +2NaOH(s)→Na2SO4(aq) +2H2O(l)

*This additionally balances the variety of O. The number of S is already balanced.

Now the we have a balanced equation, we deserve to determine exactly how much H2O is produced.


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Problem Details

Aqueous sulfuric mountain (H2SO4) will certainly react with solid sodium hydroxide (NaOH) to produce aqueous salt sulfate (Na2SO4) and liquid water (H2O). Suppose 93 g of sulfuric acid is blended with 128 g of sodium hydroxide. Calculation the maximum fixed of water that could be produced by the chemical reaction. Round your answer to 2 far-reaching digits.


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