Notice that us are provided the massive of both reactants: this method we require to determine thelimiting reactant, i beg your pardon is the reactant that creates the much less amount the product.

You are watching: Reaction of sodium bicarbonate and hydrochloric acid

This is since once the limiting reactant is all offered up, the reaction deserve to no much longer proceed and also make more products.

This means the limiting reactant determines themaximum massive of the product (CO2) formed.

We must perform amole-to-mole comparisonbetween each reactant and CO2.

Balanced Reaction:NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)

For NaHCO3:From the well balanced equation,1 mole that NaHCO3 type 1 mole the CO2.

Themoles the CO2formed by8.67 gNaHCO3is:


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Problem Details

Sodium bicarbonate reacts through hydrochloric mountain in a gas-forming reaction to develop aqueous salt chloride, water, and also carbon dioxide gas:

NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)

Determine the mass of CO2 gas developed when 8.67 g of NaHCO3 is added to a equipment that includes 5.65 g the HCl.


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Frequently asked Questions


What scientific principle do you require to recognize in stimulate to resolve this problem?

Our tutors have indicated that to solve this trouble you will need to apply the Limiting Reagent concept. You deserve to view video clip lessons to find out Limiting Reagent. Or if girlfriend need an ext Limiting Reagent practice, girlfriend can also practice Limiting Reagent practice problems.


What professor is this difficulty relevant for?

Based on our data, us think this difficulty is appropriate for Professor Blankenship's course at UGA.


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