Multiples of #8# space #8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,144......#

Multiples of #12# space #12,24,36,48,60,72,84,96,108,120,132,144......#

Multiples of #18# are #18,36,54,72,90,108,126,144......#

Hence common multiples room #72,144,.......#

and Least typical Multiple is #72#

Another shorter method is to create numbers as multiplication that its prime factors

#8=2xx2xx2# #-># #2# comes 3 times

#12=2xx2xx3# #-># #2# comes twice and #3# once.

You are watching: Lcm of 8,12 and 18

#18=2xx3xx3# #-># #2# come once and also #3# twice

So maximum times is 3 times for #2# and two times because that #3#.

Hence, Least usual Multiple is #2xx2xx2xx3xx3=72#.

Tony B
Apr 9, 2018

Use Shwetyank"s an approach in the class and an exam. The noting schema will be set up for that approach.

#color(blue)("My different approach - helps through understanding.")#

Explanation:

Target: LCM of 8,12 and also 18.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~#color(magenta)("Once girlfriend are provided to this it need to look like")##color(magenta)("what follows (for these numbers).")#

#12=color(white)("d")8+4 color(white)("d") ->2xx4=color(white)(..)8" therefore "2xx12=24##24=18+6 color(white)("d")->3xx6=color(white)(.)18" therefore "color(white)(.)3xx24=72#

#"LCM "=72#

3 present inclusive the the answer for 3 relationships

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There are countless ways of composing any particular value so we deserve to make that look however we great as lengthy as final outcome is the exactly value. Example: 6 can and may be created as #5+1# if we so chose.

See more: How Many Calories In A Big Bag Of Cheetos Puffs Are In A Bag?

We have the right to use this to our advantage.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~#color(blue)("Answering the question")#

#color(brown)("Dealing with the 8 and 12 part")#

Write 12 together #8+4#

Now we start counting the 12"s but make sure it encompasses the 8 + 4"s. As soon as we have collected enough 4"s to make one more eight us have found the least common factor the 8 and also 12

#1: -> color(green)(12)=color(red)(8)+4##2:-> ul(color(green)(12))=color(red)(8)+ul(4 larr" include the 12"s and the 4"s")##color(white)("ddddd")color(green)(24) color(white)("ddd")ul(color(white)("ddd")color(red)(8))##color(white)("dddddddddddd")color(red)(24) larr" including all the 8"s"#

#2" the "12=24##3" the "color(white)("d")8=24#

So LCF (for 8 and 12) is 24

So we have actually a fixed proportion of 8 and also 12 in ~ every sum of 24. Consequently any kind of other product of components will need to encompass some many of 24~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~#color(brown)("Dealing through the 18 part")#

As the value of 24 locks with each other the counts that 8 and 12 we lug that forward.

Write the 24 as #18+6#

We are now counting the 24"s

#1: ->color(green)( 24)=color(red)(18)+6##2: ->color(green)(24)=color(red)(18)+6##3:->ul(color(green)(24))=color(red)(18)+ul(6larr" include the 24"s and also 6"s")##color(white)("ddddd") color(green)(72)color(white)("dddddd")ul(color(red)(18))larr" add all the 18"s"##color(white)("ddddddddddddd")color(red)(72)#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~#color(magenta)(" LCM "= 72)#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~