To deal with the equation, element the left hand next by grouping. First, left hand side requirements to it is in rewritten as 3x^2+ax+bx-16. To find a and also b, set up a device to it is in solved.

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Since ab is negative, a and b have actually the the opposite signs. Due to the fact that a+b is negative, the an unfavorable number has greater absolute worth than the positive. List all together integer bag that offer product -48. 3x2-8x-16=0 Two solutions were discovered : x = -4/3 = -1.333 x = 4 step by action solution : step 1 :Equation at the end of action 1 : (3x2 - 8x) - 16 = 0 step 2 :Trying to variable by dividing ...
3x2-+8x-16=0 Two solutions were discovered : x = -4/3 = -1.333 x = 4 action by action solution : action 1 :Equation in ~ the finish of step 1 : (3x2 - 8x) - 16 = 0 action 2 :Trying to aspect by dividing ...
2x2-8x-16=0 Two options were uncovered : x =(4-√48)/2=2-2√ 3 = -1.464 x =(4+√48)/2=2+2√ 3 = 5.464 action by action solution : step 1 :Equation in ~ the end of action 1 : (2x2 - 8x) - 16 = 0 step ...
4x2-8x-16=0 Two solutions were discovered : x =(2-√20)/2=1-√ 5 = -1.236 x =(2+√20)/2=1+√ 5 = 3.236 step by step solution : step 1 :Equation at the end of action 1 : (22x2 - 8x) - 16 = 0 step 2 ...
x2-18x-16=0 Two services were discovered : x =(18-√388)/2=9-√ 97 = -0.849 x =(18+√388)/2=9+√ 97 = 18.849 action by step solution : step 1 :Trying to aspect by dividing the center term ...
3x2-4x-16=0 Two services were found : x =(4-√208)/6=(2-2√ 13 )/3= -1.737 x =(4+√208)/6=(2+2√ 13 )/3= 3.070 step by step solution : action 1 :Equation at the finish of action 1 : (3x2 - 4x) - 16 ...
More Items     To solve the equation, aspect the left hand side by grouping. First, left hand side demands to be rewritten as 3x^2+ax+bx-16. To discover a and also b, set up a mechanism to be solved.
Since abdominal muscle is negative, a and b have the the opposite signs. Since a+b is negative, the an unfavorable number has greater absolute value than the positive. List all such integer bag that provide product -48.
All equations that the kind ax^2+bx+c=0 have the right to be fixed using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula offers two solutions, one as soon as ± is addition and one as soon as it is subtraction.
This equation is in traditional form: ax^2+bx+c=0. Substitute 3 because that a, -8 because that b, and also -16 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
Quadratic equations such together this one have the right to be resolved by completing the square. In order to complete the square, the equation must very first be in the type x^2+bx=c.

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Divide -frac83, the coefficient the the x term, by 2 to acquire -frac43. Then include the square that -frac43 come both political parties of the equation. This step makes the left hand next of the equation a perfect square.  